F(y)-F(y_0) b f(x,y)-f(x,y_0)
───── = ∫ ──────── dx
y - y_0 a y - y_0
( by F(y) 的定義 )
接著取再極限
F(y)-F(y_0)
lim ─────
y->y_0 y - y_0
b f(x,y)-f(x,y_0)
= lim ∫ ──────── dx
y->y_0 a y - y_0
b f(x,y)-f(x,y_0)
= ∫ lim ──────── dx
a y->y_0 y - y_0
( 因為 f_y (x,y) 存在
f(x,y)-f(x,y_0)
把 ──────── 定義成 f_y(x,y_0),使之連續
y - y_0
就可把 lim 放裡面 )
b
=∫ f_y(x,y_0) dx
a
這樣還有沒有漏洞?
這樣不用看到 y'
--
※ 發信站: 批踢踢實業坊(ptt.cc)
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※ 編輯: ERT312 來自: 114.39.152.137 (03/31 15:40)
※ 編輯: ERT312 來自: 114.39.152.137 (03/31 15:57)
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※ 編輯: ERT312 來自: 114.39.152.137 (03/31 16:57)
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