Re: [微積] 積分問題
※ 引述《legenthume (沒有腳毛生不如死)》之銘言：
: S (-3x^2-a)/(6x^2+a) dx
- S [(3x^2+a)/(6x^2+a)] dx = - S [1-3x^2/(6x^2+a)] dx
let x = √asinw/6, dx = (√acosw/6) dw
--> -x + S {[a(sinw)^2/2]/[a(sinw)^2]/6} (√acosw/6) dw
= -x + (√a/2) S cosw dw = -x + √asinw/2
sinw = 6x/√a
: S [-3ax^(-2)]/(3x+6/a) dx
: 這兩個積分怎麼算呢
方法跟上面那提差不多
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