Re: [中學] 三角函數

看板Math作者 (FA = ハガレン)時間14年前 (2011/09/15 10:26), 編輯推噓4(401)
留言5則, 3人參與, 最新討論串33/232 (看更多)
※ 引述《Proakis (John G. Proakis)》之銘言: Prove the identity cos(x+y)cos(x-y)=cos^2 (x) - sin^2 (y) cos(x+y)cos(x-y) = (cosxcosy - sinxsiny)(cosxcosy + sinxsiny) = cos^2(x)cos^2(y) - sin^2(x)sin^2(y) = cos^2(x)(1-sin^2(y)) - (1-cos^2(x))sin^2(y) = cos^2(x) - sin^2(y) ※ 引述《Proakis (John G. Proakis)》之銘言: Prove the identity tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x) Let x-y = A y-z = B z-x = C We have A+B+C = 0 tanA + tanB And tanC = tan(-A-B) = - tan(A+B) = - -------------- 1 - tanAtanB <=> tanC ( 1 - tanAtanB ) = - ( tanA +tanB ) <=> tanA + tanB +tanC = tanAtanBtanC -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.244.138 ※ 編輯: FAlin 來自: 140.112.244.138 (09/15 10:32)

09/15 10:33, , 1F
謝謝大大 還有一題能教教我嗎
09/15 10:33, 1F

09/15 10:33, , 2F
眼花了..原來兩題都解了
09/15 10:33, 2F

09/15 10:36, , 3F
為什麼(1-sin^2(y))跟(1-cos^2(x))=1
09/15 10:36, 3F

09/15 10:38, , 4F
在樓下那邊 ^^
09/15 10:38, 4F

09/15 17:31, , 5F
不等於1阿 展開前後消掉了]
09/15 17:31, 5F
文章代碼(AID): #1ESM9M6- (Math)
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文章代碼(AID): #1ESM9M6- (Math)