Re: [代數] 清大數學一題

看板Math作者 (摸魚中)時間13年前 (2011/04/12 04:29), 編輯推噓0(002)
留言2則, 1人參與, 最新討論串4/4 (看更多)
※ 引述《luke2 (路克:2)》之銘言: : 還有一題,我覺得無解= = : 不過我是用列舉的就是了 : p,q為正整數,且 : p^2+3q^2 =11907 : p^2+3q^2=3^5*7^2 : p^2=3(63+q)(63-q) : 求p與q的植 : 很明顯q要是3的倍數 3 | 11907 => 3| p^2+3q^2 => 3|p^2 => 3|p 3^2 | 11907 => 3^2| p^2+3q^2 => 3|q^2 => 3|q .... 3^2|q, 3^3|p Let p=3^3 r, q=3^2 s => 3 r^2 +s^2= 7^2=49 Try r =1,2,3,4 => r=4,s=1 => p=108, q=9 -- The whole problem with the world is that fools and fanatics are always so certain of themselves, but wiser people so full of doubts. – Bertrand Russell -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.116.250.190

04/12 06:13, , 1F
我當初也是一直提, 不過算不出來,唉
04/12 06:13, 1F

04/12 06:13, , 2F
謝謝!!
04/12 06:13, 2F
文章代碼(AID): #1DesIE4Z (Math)
文章代碼(AID): #1DesIE4Z (Math)