[微積] 證明題

看板Math作者 (李孟李孟)時間13年前 (2011/01/20 13:44), 編輯推噓1(102)
留言3則, 1人參與, 最新討論串2/5 (看更多)
題目如下: Let f(x+y) = f(x)+f(y) for all x and y in R. Prove that there is a number m such that f(t)= mt for all rational number t. HINT: First decide what m has to be. Then proceed in steps, starting with f(0)= 0 , f(p)= mp for p in N, f(1/p)= m/p, and so on. 像這樣的證明題...我該如何開頭如何結尾呢? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.57.70.119

01/20 17:52, , 1F
柯西法
01/20 17:52, 1F

01/20 17:54, , 2F
http://0rz.tw/YC3VG , 最後 Q→R 的部份如下:
01/20 17:54, 2F

01/20 17:55, , 3F
噢 ... 題目沒有要證到 R, 請忽略上面那句 Orz
01/20 17:55, 3F
文章代碼(AID): #1DDykiFK (Math)
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文章代碼(AID): #1DDykiFK (Math)