Re: [理工] [工數]-二階ODE
※ 引述《gn01178479 (787878)》之銘言:
: d^2u / dx^2 = xe^y , u(0,y) = y^2 , u(1,y)=siny
: 先從dx^2著手好呢 還是有其他的解法
: 麻煩各位了
令v = du/dx
y
dv = xe dx
1 2 y
v = ---x e + f(y)
2
1 2 y
du = [--- x e + f(y)]dx
2
1 3 y
u = --- x e + xf(y) +g(y)
6
當 x = 0
2
y = g(y)
當x = 1
1 y 2
siny = --- e + f(y) + y
6
1 y 2
f(y) = siny - --- e - y
6
1 3 y 1 y 2 2
u = --- x e + x(siny - --- e - y) + y
6 6
感覺有錯耶XDDDDD(逃..)
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◆ From: 118.167.132.42
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04/06 22:53, , 1F
04/06 22:53, 1F
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04/06 22:53, , 2F
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發現加減號有錯 XDDD
※ 編輯: honestonly 來自: 118.167.132.42 (04/06 22:56)
推
04/06 23:08, , 3F
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04/06 23:18, , 4F
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討論串 (同標題文章)