Re: [理工] [工數]-一階ODE
※ 引述《yooter231 (yooter)》之銘言：
: dy/dx=1/(x-y+1) y(1)=0
: 這...我毫無頭緒
dy 1 dx
---- = ----------- ==> ---- = x - y + 1
dx x - y + 1 dy
==> x' - x = 1-y 為一階ODE
I = exp[∫-1dy] = e^-y
Ix = ∫e^-y - ye^-y dy = ye^-y + c
x = y + ce^-y
--
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