Re: [理工] [工數] 拉氏轉換
睡前騙一下P弊
1
y = ----- f(x)
D+λ
(D+λ)y=f(x)
dy + λydx = f(x)dx
λx
積分因子I = exp[∫λdx] = e
λx λx
d(ye ) = e f(x)dx
λx λx
ye = ∫ e f(x)dx
-λx λx
y = e ∫ e f(x)dx + c
解特解就沒有c了喔
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◆ From: 118.167.132.186
※ 編輯: honestonly 來自: 118.167.132.186 (03/09 21:53)
推
03/09 21:54, , 1F
03/09 21:54, 1F
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03/09 21:56, , 2F
03/09 21:56, 2F
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03/09 21:56, , 3F
03/09 21:56, 3F
推
03/09 21:58, , 4F
03/09 21:58, 4F
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