[理工] [工數]-O.D.E.
2 2
y''+y=1-(t / π ) 0≦t≦π
I.C. y(0)=y'(0)=0
這個我知道前面 y = c1 cos t + c2 sin t
h
但是後面要怎麼解?!
2 2 2 2
可得到答案 y(t)=-(1+(2 / π ))cos t - t /π +1 +2/π
再次麻煩高手指教了!!感謝!!
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