[理工] [工數]-複變
證明:
∞ ln(x^2 + 1)
∫ _____________ dx = πln2
0 x^2 + 1
解答起手式這樣寫
考慮: ln(z+i)
∮ _________ dz ,c包含實軸上-R到R的線段及(上)半圓
c z^2 + 1
為什麼他知道要令 ln(z+i)這項 !?
如果不這樣假設的話算的出來嗎
拜託各位高手解答一下...感激不盡
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