[理工] [工數]-一階ODE
[xy(x^2 - y^2)^(1/2) + x]y'=y - x^2 *(x^2 - y^2)^(1/2)
拜託版上高手了@@
再補一題..x^2*y'' + x(2x + 1/2)y' + [x- (1/2)]y =0
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※ 編輯: kagato 來自: 118.171.77.81 (10/12 18:59)
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