[請益] 雞兔問題
小明家養了雞及兔子共88隻,其中雞的腳數比兔的腳數少22隻
問雞、兔各有多少隻??
我的解是設未知數來解的
設雞有x隻,則兔有88-x隻
所以2x=4x(88-x)-22
x=55(雞)則兔33
但解答上的解是
88x4=352
352-22=330
330/6=55(雞)
88-55=33(兔)
不知有老師可以和我解說一下,這式子的算法是怎來的??
謝謝!!
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