Re: [請益] 國一下 二元一次方程式@@"
※ 引述《elfyukikaze (同人小說之路(?))》之銘言:
: 一線過(2,-1) 與X軸交(a,0) 交y軸(0,b) 且ab不等於0
: 試求2b-a-ab+3=?
:
A(2,-1) B(a,0) C(0,b)
--- --- -b 1
BC = BA ==> --- = ----
a a-2
交叉相乘可得a=-ab+2b
帶回原方程式即可..
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