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作者 suker 在 PTT [ trans_math ] 看板的留言(推文), 共126則
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2F→: (T/S)^(-1.1) 第一行打錯 S=0.00275T 值是對的10/10 09:20
3F→: 印象中有回過 有砍掉了?10/10 09:21
4F→: 看錯抱歉~10/10 09:23
3F→: 積分因子不是唯一的 可以用就用06/02 11:32
2F→:常除法118.169.82.253 03/31 22:07
3F→:OK阿你答案可以 只是要加不定積分常數118.169.89.19 12/07 01:07
4F→:(cosx)^(-1) 次方 微分爾以118.169.89.172 11/10 21:10
5F→:(-1)* (cosx)^(-2) * (-sinx) =tanx*secx118.169.89.172 11/10 21:12
2F→:2. 已經有理化了阿 分母又沒根號?118.169.82.39 09/30 13:15
2F→:把不等式取極限也是limit (x√x -1) =0118.169.77.12 01/08 21:32
3F→:開x次方暫用x√x代替不好打 原式=1118.169.77.12 01/08 21:33
6F→:y=y(x) ; e^{y(x)}對x微分 e^y(x) * y'(x)118.169.79.55 11/23 21:31
7F→:{sin(x^2)}' ={cos(x^2)}*{x^2}' =2x*cosx^2118.169.79.55 11/23 21:34
8F→:後面的 {x^2}' 就是連鎖律118.169.79.55 11/23 21:34
1F→: sin√3-sin√3=0 剩下delta / delta =1?118.169.79.237 11/20 11:57
2F→:有教羅畢達公式 0/0 在上下微分118.169.79.237 11/20 14:03
3F→:{cos(√(3+△Θ))/ (2√(3+△Θ))}/1118.169.79.237 11/20 14:08
4F→:Δθ->0 ; (cos√3) /(2√3)118.169.79.237 11/20 14:08
8F→:[sin√(3+x)]' =cos(√(3+x)) *(√(3+x))'118.169.79.237 11/20 15:36
9F→:=cos(√(3+x)) *(1/2)*(3+x)^(-1/2)118.169.79.237 11/20 15:38
10F→:=cos(√(3+x)) / (2√(3+x))118.169.79.237 11/20 15:38
13F→:常數微分=0 所以直接是0118.169.79.237 11/20 16:59
3F→:cos(0)=1.cos(π)=-1, -5OK118.169.78.90 11/18 21:49