Re: [積分] 多項式積分
: 3x+7
: 1.∫----------- dx
: x^2-x+2
(3/2)(2x-1) + (17/2)
= ∫--------------------- dx
x^2 - x + 2
=(3/2)ln( x^2 - x + 2) + (17/2) * ∫ 1/[(x - 0.5)^2 + (7/4)]
-1
=(3/2)ln( x^2 - x + 2) + (17/2) * { (2/√7) * tan [ (2x-1)/√7 ] } + C
-1
=(3/2)ln( x^2 - x + 2) + (17/√7) * tan [ (2x-1)/√7 ] + C
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