Re: [微分] 極值問題2
※ 引述《henry925 ( 小亨利)》之銘言：
: f(x) = 5(x-1)^(2/3) - 2(x-1)^(5/3) 之極大、極小值 ?
f' = (10/3)((x-1)^(-1/3))- (10/3)((x-1)^(2/3))
= (10/3) (2 - x)((x-1)^(-1/3)) = 0或不存在
=> x = 1,2 (critical points)
x | | 1 | | 2 |
-------------------------
f'| - | X | + | 0 | -
-------------------------
f | ↘ | 0 | ↗ | 3 | ↘
由圖表得知
f(1)=0 為相對極小值
{
f(2)=3 為相對極大值
f(-∞)=∞為絕對極大值
{
f(∞)=-∞為絕對極小值
有錯請指正~
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◆ From: 219.70.179.171
※ 編輯: Qmmm 來自: 219.70.179.171 (11/20 23:46)
推
11/21 01:02, , 1F
11/21 01:02, 1F
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11/21 01:03, , 2F
11/21 01:03, 2F
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11/21 10:31, , 3F
11/21 10:31, 3F
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11/21 10:38, , 4F
11/21 10:38, 4F
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11/21 10:56, , 5F
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11/21 10:57, , 6F
11/21 10:57, 6F
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11/21 10:57, , 7F
11/21 10:57, 7F
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11/21 11:00, , 8F
11/21 11:00, 8F
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11/21 11:00, , 9F
11/21 11:00, 9F
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11/21 11:02, , 10F
11/21 11:02, 10F
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11/21 11:02, , 11F
11/21 11:02, 11F
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11/21 11:02, , 12F
11/21 11:02, 12F
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11/21 11:30, , 13F
11/21 11:30, 13F
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11/21 11:30, , 14F
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11/21 11:32, , 15F
11/21 11:32, 15F
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11/21 11:32, , 16F
11/21 11:32, 16F
※ 編輯: Qmmm 來自: 219.70.179.171 (11/21 12:15)
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04/22 18:01,
6年前
, 17F
04/22 18:01, 17F
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