Re: [微分] 一題微分
※ 引述《illega1 (手術之鬼)》之銘言:
: 求 lim (sinx)^[sinx - x]
: x->0+
sinx
lim sinx
x->0+ 1
= -------------- = --- =1
x 1
lim sinx
x->0+
: ans = 1
--
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◆ From: 61.229.69.177
※ 編輯: youyouyou 來自: 61.229.69.177 (05/29 10:00)
推
218.184.82.118 05/29, , 1F
218.184.82.118 05/29, 1F
推
140.115.213.118 05/29, , 2F
140.115.213.118 05/29, 2F
推
220.134.23.210 05/29, , 3F
220.134.23.210 05/29, 3F
推
140.115.213.118 05/29, , 4F
140.115.213.118 05/29, 4F
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140.115.213.118 05/29, , 5F
140.115.213.118 05/29, 5F
推
218.184.82.118 05/29, , 6F
218.184.82.118 05/29, 6F
指數是負的~~
相當是除 (應該沒有錯巴~~這是高中數學,我高中數學不好)
x
所以把sinx 般去分母
上下極限皆存在~~故可解
不知道有回答到嘛?
※ 編輯: youyouyou 來自: 140.115.213.118 (05/29 21:59)
推
218.166.63.235 05/30, , 7F
218.166.63.235 05/30, 7F
推
218.166.140.27 05/30, , 8F
218.166.140.27 05/30, 8F
推
218.166.63.235 05/30, , 9F
218.166.63.235 05/30, 9F
推
218.166.59.195 05/31, , 10F
218.166.59.195 05/31, 10F
推
218.175.128.121 06/07, , 11F
218.175.128.121 06/07, 11F
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