Re: [微分] 一題微分
※ 引述《youyouyou (成大或台大嚕~幹)》之銘言：
: ※ 引述《youyouyou (成大或台大嚕~幹)》之銘言：
: ※ 引述《illega1 (手術之鬼)》之銘言：
: : 求 lim (sinx)^[sinx - x]
: : x->0+
: sinx
: lim sinx
: x->0+ 1
: = -------------- = --- =1
: x 1
: lim sinx
: x->0+
x
lim sinx = 1
x->0+
這邊很直觀沒錯
但是如果考試這樣寫....有機會會錯 還是要說明一下
*
lim x ln (sin x) = lim ln(sin x)/(1/x) = lim -x^2/sinx = 0
x->0+
所以
x
lim sinx = 1
x->0+
: : ans = 1
--
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