Re: [閒聊] 微數學之塔-為什麼雙妲己不可能IMBA
令1.x為妲己額外增加x倍combo傷害,X是非負實數。
2.n為combo數,n>=1。
雙妲倍率 (n-1)(0.25+2x)+1
3.f_n(x) = ───── = ──────── 為一非負函數列
單妲倍率 (n-1)(0.25+x) +1
則不難簡化成
4x
f_n(x) = 1 + ─────────
4
1 + 4x + ───
n-1
~~~~~~~~~~~~~~~~~~
↓
(1) €[0,1),for all x>=0, n>=1
4x
(2) for each x>=0, f_n(x)絕對遞增至 ──── ,令此為f(x)
1 + 4x
(3) f(x)絕對遞增至1
謝謝板友online135畫圖:http://imgur.com/zApZjKn

圖解:妲己加成x即便到無窮大,雙妲/單妲仍是不到兩倍
翻譯米糕:
同藍羊,雙妲是單妲的不到兩倍,不論任何combo與妲己加成多少。
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還以為要用到泰勒展開...
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我是看到你文中有講到"忽略"
一時興起想用泰勒展開式去看忽略掉的誤差是多少
結果好像不用,連微分都不必了XDDD
謝謝靈感~
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※ 編輯: znmkhxrw (61.231.123.51), 07/14/2014 23:24:03
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謝謝豬女老公,最後結果差不多
2x
f_n(x) = 1 + ─────────
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※ 編輯: znmkhxrw (61.231.123.51), 07/14/2014 23:31:20
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※ 編輯: znmkhxrw (61.231.123.51), 07/14/2014 23:43:48
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看到了 謝啦!
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※ 編輯: znmkhxrw (61.231.123.51), 07/14/2014 23:44:41
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