Re: [解題] 高二物理斜碰撞恢復係數是否必定正一
v、u 為碰撞前速度 V、U 為碰撞後速度 均為向量
mv + Mu = mV + MU -----------------(1)
(1/2) mv^2 + (1/2) Mu^2 = (1/2) mV^2 + (1/2) MU^2 ----------(2)
(1) => m(v-V) = -M(u-U) ----------------(3)
(2) => m(v^2-V^2) = -M(u^2-U^2)
=> m(v-V)˙(v+V) = -M(u-U)˙(u+U) --------------(4)
(3)代入(4)
=> (v+V)˙n = (u+U)˙n
=> (v-u)˙n = (U-V)˙n
n≡ (v-V)/(|v-V|) = -(u-U)/(|u-U|)
恢復系數當然就1
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 118.169.219.193
推
09/06 23:19, , 1F
09/06 23:19, 1F
推
09/07 10:47, , 2F
09/07 10:47, 2F
→
09/07 10:48, , 3F
09/07 10:48, 3F
→
09/07 10:48, , 4F
09/07 10:48, 4F
推
09/07 11:09, , 5F
09/07 11:09, 5F
→
09/07 11:10, , 6F
09/07 11:10, 6F
→
09/07 11:10, , 7F
09/07 11:10, 7F
→
09/07 11:35, , 8F
09/07 11:35, 8F
→
09/07 23:50, , 9F
09/07 23:50, 9F
→
09/07 23:56, , 10F
09/07 23:56, 10F
→
09/07 23:58, , 11F
09/07 23:58, 11F
→
09/08 00:22, , 12F
09/08 00:22, 12F
→
09/08 00:48, , 13F
09/08 00:48, 13F
討論串 (同標題文章)
以下文章回應了本文：
完整討論串 (本文為第 4 之 8 篇)：