[問題] 力矩的問題= =
我們常說計算力矩時支點可以任取
但我有以下的例子,支點若是任取會矛盾
想請大大幫我看一下觀念哪裡有錯?
場景:太空中
物體:均勻長木棒(長度d)
狀況:從B點施力F推動
問題:若是取O點當支點,則力矩為順時針F X d/2,木棒會轉--->合理
若是取B點當支點,則力矩為0,但常理判斷木棒會轉--->矛盾!!!!
***********************************
***********************************
O B
^
| F
|
請問問題的徵結在哪裡呢?
謝謝!!
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 118.165.169.95
推
06/30 10:15, , 1F
06/30 10:15, 1F
→
06/30 10:17, , 2F
06/30 10:17, 2F
推
06/30 10:36, , 3F
06/30 10:36, 3F
→
06/30 10:37, , 4F
06/30 10:37, 4F
→
06/30 10:38, , 5F
06/30 10:38, 5F
→
06/30 10:39, , 6F
06/30 10:39, 6F
→
06/30 10:39, , 7F
06/30 10:39, 7F
推
06/30 10:44, , 8F
06/30 10:44, 8F
→
06/30 10:45, , 9F
06/30 10:45, 9F
推
06/30 10:48, , 10F
06/30 10:48, 10F
→
06/30 10:58, , 11F
06/30 10:58, 11F
→
06/30 10:58, , 12F
06/30 10:58, 12F
推
06/30 14:04, , 13F
06/30 14:04, 13F
→
06/30 14:05, , 14F
06/30 14:05, 14F
→
06/30 14:05, , 15F
06/30 14:05, 15F
→
06/30 14:06, , 16F
06/30 14:06, 16F
推
06/30 22:40, , 17F
06/30 22:40, 17F
→
06/30 22:42, , 18F
06/30 22:42, 18F
→
06/30 22:43, , 19F
06/30 22:43, 19F
→
06/30 22:45, , 20F
06/30 22:45, 20F
推
07/01 19:32, , 21F
07/01 19:32, 21F
→
07/01 19:33, , 22F
07/01 19:33, 22F
推
07/03 11:40, , 23F
07/03 11:40, 23F
推
07/03 12:24, , 24F
07/03 12:24, 24F
推
08/31 05:03, , 25F
08/31 05:03, 25F
討論串 (同標題文章)