Re: [問題] A班靜力學的題目

看板NTUMEB98作者haowei37 (Hao)時間14年前 (2009/11/02 17:29)推噓3(3推 0噓 0→)

留言3則, 3人參與討論串2/2 (看更多)

5.142 r=CB(0.3125,0,-1) R=CA(0.5,0,-1.6) F1=Fd/2.18(-1.5625,0.875,1.25) F2=Fe/2.18(-1.5625,-0.875,1.25) F3=(0,67.5,42.75) M1=r X F1=(0.3125,0,-1)XF1 =Fd/2.18(0.875,1.1718,0.273) M2=r X F2=Fe/2.18(-0.875,1.1718,-0.273) M3=R X F3=(108,-21.37,33.75) M1+M2+M3=0 Fd/2.18*1.1718+Fe/2.18*1.1718+(-21.37)=0 Fd+Fe=39.76 Fd/2.18*0.875+Fe/2.18*(-0.875)+108=0 Fd-Fe=-269.51 Fd=-114.88 Fe=154.64 感謝B班林政賢提供XD -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.7.59

推

sirius733

11/02 18:13, , 1^F

11/02 18:13, 1^F

推

physicsdk

11/02 19:31, , 2^F

11/02 19:31, 2^F

推

thatismyway

11/02 21:13, , 3^F

11/02 21:13, 3^F