Re: [中學] 指對數1題
: 整理到最後次方有點混亂@@" 請教~
(1/2)^t = -log_2 (t) = log_(1/2) (t)
t為y = (1/2)^x和y = log_(1/2) (x)的交點
又y = (1/2)^x和y = log_(1/2) (x)對稱於y = t
可知y = t = (1/2)^t = log_(1/2) (t)
=> t^(1/t) = 1/2
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