Re: [分析] bounded vs. convergent subsequence

看板Math作者 (va)時間9年前 (2016/07/10 21:00), 編輯推噓0(004)
留言4則, 3人參與, 最新討論串3/5 (看更多)
※ 引述《GSXSP (Gloria)》之銘言: : Q1: : f_k (i) uniformly bounded for all i = 1, 2 ,... : Can we find a subsequence k_j such that : f_{k_j} (i) converge for all i=1,2,... f_k (i) = 1 if k = 0 mod i 1/2 if k = 1 mod i 1/3 if k = 2 mod i 1/4 if k = 3 mod i ...... ...... 1/i if k = i-1 mod i maybe this f_k(i) can't find a f_{k_j} (i) converge for all i=1,2,... -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 220.133.89.48 ※ 文章網址: https://www.ptt.cc/bbs/Math/M.1468155646.A.94B.html

07/10 23:11, , 1F
f_k (3) k>3 is not defined?
07/10 23:11, 1F

07/11 14:45, , 2F
f_k(i)=1/i if k = i-1 mod i for i=1,2,3,4,....
07/11 14:45, 2F

07/11 15:22, , 3F
Then what is f_5(3)?
07/11 15:22, 3F

07/12 17:00, , 4F
可以啊, k_j := j!的話, f_{k_j}(i) = 1 for j>i.
07/12 17:00, 4F
文章代碼(AID): #1NWaR-bB (Math)
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文章代碼(AID): #1NWaR-bB (Math)