[微積] 三角函數積分問題
∫sinxcosx dx =∫sinxdsinx=sin平方x/2
∫sinxcosx dx =∫-cosxdcosx=-cos平方x/2=(sin平方x -1) /2
試問這兩個結果都對嗎 假如對為什麼會不一樣
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推
09/24 15:54, , 1F
09/24 15:54, 1F
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09/24 15:54, , 2F
09/24 15:54, 2F
推
09/24 15:56, , 3F
09/24 15:56, 3F
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09/24 17:18, , 4F
09/24 17:18, 4F
推
09/24 18:47, , 5F
09/24 18:47, 5F
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09/24 19:16, , 6F
09/24 19:16, 6F
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09/24 22:06, , 7F
09/24 22:06, 7F
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09/24 23:08, , 8F
09/24 23:08, 8F
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