Re: [微積] 積分
※ 引述《SmallLuLu (小嚕嚕)》之銘言:
: arctanx
: ∫ ---------- dx = ?
: x^2
x = tan(y)
∫ycot^2(y)dtan(y)
= ∫ycot^2(y)sec^2(y)
= ∫ycsc^2(y))dy
= -ycot(y) + ∫cot(y)
= -arctan(x)/x + ln|sin(x)|
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 42.72.103.190
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06/10 23:35, , 1F
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※ 編輯: elfkiller 來自: 42.72.103.190 (06/10 23:43)
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