Re: [微積] 積分
※ 引述《illega1 (原汁原味蒸男人。)》之銘言:
: 1 x^b - x^a
: S ----------- dx = ?......a,b>0
: 0 lnx
1 x^b - x^a 1 b
∫ ----------- dx = ∫ ∫ x^y dy dx
0 lnx 0 a
b 1 b x^[y+1] |1
= ∫ ∫ x^y dx dy = ∫ ---------- | dy
a 0 a y+1 |0
b 1 b + 1
= ∫ --------- dy = ln[-------]
a y + 1 a + 1
--
※ 發信站: 批踢踢實業坊(ptt.cc)
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