[理工] [工數] PDE
請問大家
@U @^2U
---= ------ -Ke^(-t)
@t @ x^2
U=U(x,t)
U(0,t)=U(L,t)=0
U(x,0)=f(x)
如果要用特徵函數展開
由邊界條件可以知道
U(x,t)=ΣA(t)sin(nπx/L)
請問大家
關於 Ke^(-t)
該怎麼用特徵函數展開??
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