[理工] [工數] PDE
d^2 ψ d^2 ψ
─── + ─── = A。A是個常數 x>0,y>0
d x^2 d y^2
B.C ψ(0,y)=ψ(a,y)=b b常數
ψ(x,0)=b ψ(x,a)=0
這樣的一個非齊性pde怎解?
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推
11/19 22:20, , 1F
11/19 22:20, 1F
推
11/19 22:25, , 2F
11/19 22:25, 2F
→
11/19 22:25, , 3F
11/19 22:25, 3F
推
11/20 01:46, , 4F
11/20 01:46, 4F
→
11/20 01:47, , 5F
11/20 01:47, 5F
推
11/20 01:53, , 6F
11/20 01:53, 6F
→
11/20 02:14, , 7F
11/20 02:14, 7F
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