Re: [理工] [線代]-row(A)
作者: funtsung (funtsung) 看板: Grad-ProbAsk
標題: Re: [理工] [線代]-row(A)
時間: Mon Mar 22 00:38:26 2010
: : 2.
: : [ 1 -1 1 -1]
: : [-1 1 -1 1]
: : A = [ 2 -2 2 -2]
: : [-2 2 -2 2]
: : 求 特徵值 特徵向量
: : [ 1-λ -1 1 -1 ] (1)
: : =[-1 1-λ -1 1 ] (2) (1)+(2)
: : [ 2 -2 2-λ -2 ] (3) (1)*-2+(2)
: : [-2 2 -2 2-λ] (4) (1)*2+(2)
[1-λ -1 1 -1 ]
= [ -λ -λ 0 0 ]
[2λ 0 -λ 0 ]
[-2λ 0 0 -λ]
[1-λ -1 1 -1]
= -(λ^3) [1 1 0 0]
[-2 0 1 0]
[2 0 0 1]
[6-λ 0 0 0]
=-(λ^3) [1 1 0 0] = -(λ^3)*(6-λ)
[-2 0 1 0] #
[2 0 0 1]
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※ 編輯: funtsung 來自: 114.26.188.120 (03/22 00:48)
※ 編輯: funtsung 來自: 114.26.188.120 (03/22 00:52)
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