[理工] [工數]-ODE
1. Find the general solution of
dx dy
---- + ---- + 2y = sint
dt dt
dx dy
---- + ---- - x - y = 0
dt dt
答案
t 1
y = ce + ---sint
2
t 1
x = -3ce - ---sint
2
我的做法
Dx + (D+2)y = sint
(D-1)x + (D-1)y = 0
[x] [D D+2][x] sint
= =
[y] [D-1 D-1][y] 0
sint D+2
0 D-1 -1 -1
x = ------------- = ---[sint(D-1)] = ---[cost - sint]
D D+2 2 2
D-1 D-1
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推
02/13 17:35, , 1F
02/13 17:35, 1F
推
02/13 17:35, , 2F
02/13 17:35, 2F
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02/13 17:37, , 3F
02/13 17:37, 3F
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02/13 17:46, , 4F
02/13 17:46, 4F
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02/13 19:24, , 5F
02/13 19:24, 5F
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02/13 19:33, , 6F
02/13 19:33, 6F
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02/13 21:16, , 7F
02/13 21:16, 7F
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02/13 21:16, , 8F
02/13 21:16, 8F
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02/13 21:35, , 9F
02/13 21:35, 9F
推
02/14 14:02, , 10F
02/14 14:02, 10F
※ 編輯: mdpming 來自: 61.230.184.53 (02/14 21:18)
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