[理工] [工數]-矩陣
Find a Jordan canonical form of the matrix
_ _
∣1 -1 0 1 ∣
A=∣0 2 -1 0 ∣
∣0 1 0 0 ∣
∣0 -1 0 2 ∣
﹉ ﹉
Ans: _ _ _ _
∣1 -1 0 1 ∣ -1 ∣1 0 0 0 ∣
P =∣0 -1 1 0 ∣ P A P =∣0 1 1 0 ∣
∣0 -1 2 0 ∣ ∣0 0 1 0 ∣
∣0 -1 0 1 ∣ ∣0 0 0 2 ∣
﹉ ﹉ ﹉ ﹉
遲來的題目~~
這題算出來的特徵值1對應的特徵向量可以用廣義特徵向量求出?-1-1-1-1那行我算不出來
請各位指點迷津
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◆ From: 124.218.210.146
※ 編輯: zendla 來自: 124.218.210.146 (02/09 00:07)
→
02/09 00:06, , 1F
02/09 00:06, 1F
推
02/09 00:06, , 2F
02/09 00:06, 2F
→
02/09 00:07, , 3F
02/09 00:07, 3F
推
02/09 00:07, , 4F
02/09 00:07, 4F
推
02/09 00:08, , 5F
02/09 00:08, 5F
→
02/09 00:08, , 6F
02/09 00:08, 6F
※ 編輯: zendla 來自: 124.218.210.146 (02/09 00:20)
推
02/09 00:10, , 7F
02/09 00:10, 7F
→
02/09 00:12, , 8F
02/09 00:12, 8F
推
02/09 00:12, , 9F
02/09 00:12, 9F
推
02/09 00:20, , 10F
02/09 00:20, 10F
推
02/09 00:27, , 11F
02/09 00:27, 11F
→
02/09 00:27, , 12F
02/09 00:27, 12F
推
02/09 00:28, , 13F
02/09 00:28, 13F
推
02/09 00:48, , 14F
02/09 00:48, 14F
→
02/09 00:49, , 15F
02/09 00:49, 15F
→
02/09 01:02, , 16F
02/09 01:02, 16F
→
02/09 01:05, , 17F
02/09 01:05, 17F
→
02/09 01:08, , 18F
02/09 01:08, 18F
→
02/09 01:10, , 19F
02/09 01:10, 19F
→
02/09 01:20, , 20F
02/09 01:20, 20F
→
02/09 01:27, , 21F
02/09 01:27, 21F
→
02/09 02:17, , 22F
02/09 02:17, 22F
推
02/09 10:18, , 23F
02/09 10:18, 23F
→
02/09 10:26, , 24F
02/09 10:26, 24F
推
02/09 10:31, , 25F
02/09 10:31, 25F
→
02/09 11:56, , 26F
02/09 11:56, 26F
→
02/09 11:56, , 27F
02/09 11:56, 27F
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