[理工] [工數]-拉氏
-1 se^-s
L [──────────]
(s+1)^2 (s^2 +2s+2)
-1 s
=u(t-1)L [──────────]
(s+1)^2 (s^2 +2s+2)
-1 s+1 1
=u(t-1)L [──── - ────]
(s+1)^4 (s+1)^4
-1 1 -1 1
=u(t-1){L [────] - L [─────]}
(s+1)^3 (S+1)^4 t=t-a
1
=u(t-1)[0.5(t-1)^2 e^(-t+1) - ──(t-1)^3 e^(-t+1) ]
6
麻煩各位大大幫我看一下到這邊有錯嗎 我答案跟課本不同= = 謝謝
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