Re: [理工] [工數]-ODE
※ 引述《wil0829ly (汪汪)》之銘言：
: 2
: y"-y'-12y=2sinh x
: 4x -3x 1 2x 1 -2x 1
: <解> y=c1e +c2e -──e -──e +──
: 20 12 12
逆運算是展開成
2*[1/2 (e^x - e^-x)* 1/2(e^x - e^-x)]
=1/2(e^2x - e^-2x)
是這樣嗎??
我做不出原po的答案耶
各位大大幫看一下吧
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◆ From: 122.116.171.226
推
11/21 00:38, , 1F
11/21 00:38, 1F
推
11/21 00:39, , 2F
11/21 00:39, 2F
Yp=(D^2-D-12)1/2 e^2x - (D^2-D-12)1/2 e^-2x
=-5e^2x -3e^-2x
※ 編輯: JaLunPa 來自: 122.116.171.226 (11/21 00:43)
推
11/21 00:46, , 3F
11/21 00:46, 3F
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11/21 00:48, , 4F
11/21 00:48, 4F
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11/21 00:48, , 5F
11/21 00:48, 5F
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11/21 00:48, , 6F
11/21 00:48, 6F
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11/21 00:49, , 7F
11/21 00:49, 7F
推
11/21 18:43, , 8F
11/21 18:43, 8F
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11/21 18:45, , 9F
11/21 18:45, 9F
推
11/21 18:58, , 10F
11/21 18:58, 10F
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11/21 22:08, , 11F
11/21 22:08, 11F
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11/22 19:33, , 12F
11/22 19:33, 12F
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