[理工] [工數]-ODE
Solve
y''=x (y')^3
我的解法是
p=y'
p'=y''
then
p'=x(p)^3
dp/dx =x p^3
dp/p^3 - x dx =0
p^-2 + x^2 =c1
c1-x^2 =( dp/dx )^-2
dp/dx =( c1-x^2 )^(-1/2)
p= S ( c1-x^2 )^(-1/2) dx
這裡我做不太下去了!!!
請問大家接下來該怎麼辦!!!
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