Re: [理工] [工數]-高階ode
1. let Y'=z
dy dz
y''=--- ---=zz'
dx dy
yzz'=z^2-z
yz'=z-1
lnz-1=lny +c'
z=y'=c1y+1
1
---ln(c1y+1)=x+c2
c1
--
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