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作者 positMIT 在 PTT [ Grad-ProbAsk ] 看板的留言(推文), 共15則
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13F推: push01/26 21:43
2F→: S->R S的 x-'y'->R的 'x'-y S的輸出就是R的輸入01/20 09:15
3F→: 所以中間的變數要設一樣01/20 09:15
1F推:你可以把1/Rf想成另一個gm值(∵Rf值越小,經過Rf電流越大)03/21 17:32
2F→:只要放大器的gm>1/Rf,則Feedforward可視為Amp獨自貢獻03/21 17:34
3F→:事實上Rf對Vout有前饋貢獻,一般因計算太複雜不考慮.03/21 17:36
4F→:另外feedback公式成立條件:訊號必全流過β網路(ie,電流無03/21 17:41
5F→:分流,電壓無耗損)03/21 17:41
2F推:直接把Rpi和Re當做並聯電阻 Ix完全流入寫兩條KCL就解得02/16 01:35
3F→:建議不要用Rq來等效,直接用電流想法去解釋 (Vx擺在C極)02/16 01:36
1F推:12. M2 M4 Vgs一樣 故Vov相同 Vo(min)=Vov3+Vgs402/15 02:13
2F→: 比例關係求得Vov3=1/2 *0.2=0.1 Vo(min)= 0.1+0.8=0.9V02/15 02:14
3F→:16. yes02/15 02:14
5F推:ID3=ID4 電流相同 (W/L)3*Vov3^2 = (W/L)4*Vov4^202/15 10:49
4F推:推02/02 12:48
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