[解題] 數學
問題: 當n大於多少以後,2^n 有十位數?(log2=0.0310)
a.29 b.30 c.33 d.34
我的解法:
10^9 = < x < 10^10
兩邊取log
9 = < n log 2 < 10
29.9... = < n < 33.22....
我選了a 可是答案是b
我邏輯上出了問題了嗎? 謝謝!!
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