Re: [考古]help me
※ 引述《orlando1988 (orlando)》之銘言：
: lim(1-1/2n)^3n =??
: n->OO
令y=(1-1/2n)^3n lny= ln(1 - 1/2n)/(1/3n)
1/{(2n^2)(1 - 1/2n)}
lim lny = lim ----------------------- = -3/2 = ln( lim y ) (因y=lnx在x>0連續)
n→∞ n→∞ -1/3n^2 n→∞
得
lim(1-1/2n)^3n = e^(-3/2)
n→∞
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