Re: [考古] 積分
推
07/06 16:48,
07/06 16:48
x
t = tan(---)
2
x -1
--- = tan (t)
2
1 1 2
--- dx = --------- dt => dx = --------- dt
2 1 + t^2 1 + t^2
--
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推
07/06 16:57, , 1F
07/06 16:57, 1F
→
07/06 16:57, , 2F
07/06 16:57, 2F
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