Re: [級數]
method 2
1
f(x) = --------- = (1-x)^-2 =
(1-x)^2
-2 -2 0 -2 -3 1 -2 -4 2
C (1) (-X) + C (1) (-X) + C (1) (-X) + ... =
0 1 2
1 + 2x + 3x^2 + ... =
∞
Σ (n+1)x^n
n=0 #
※ 編輯: flyfound 來自: 218.166.206.14 (07/04 00:56)
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