Re: [極限] 兩題
※ 引述《Jasy (面對現實)》之銘言：
: lim x^x^x =?
: x→0
x->0+ lim x^x = 1
so x->0+ lim x^x^x = lim x^(1) =0^1 =0
and lim x^x^x^x = 1
x->0+
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