Re: [問題] 因式分解
※ 引述《elongoria (longoria)》之銘言：
: 題目是這樣的
: (x+1)(2x+1)(3x-1)(4x-1)-36x^4
= (x+1)(3x-1)(2x+1)(4x-1) - 36x^4
= (3x^2 + 2x - 1)(8x^2 + 2x - 1) - 36x^4
= [24x^4 + 11x^2(2x - 1) + (2x - 1)^2] - 36x^4
= [-12x^4 + 11x^2(2x - 1) + (2x - 1)^2] 令(2x - 1) = t, x^2 = s
= [-12s^2 + 11st + t^2]
= [(-12s + t)(s+t)]
= [(-12x^2 + 2x - 1)(x^2 - 2x + 1)]
= [(-12x^2 + 2x - 1)(x-1)^2]
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