討論串[力學] 震盪
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內容預覽:
(1/2)kx^2 + mgx + (1/2)Iw^2 + (1/2)mv^2 = E. => (1/2)k[x + mg/k]^2 - (1/2)(1/k)(mg)^2 + (1/2)[M/2 + m] R^2 w^2 = E. => -(1/2)(1/k)(mg)^2 + (1/2)[M/2 +
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內容預覽:
mg - T_1 = mx". T_1R - T_2R = (1/2)MR^2 (x" / R). => T_1 - T_2 = (1/2)Mx". T_2 = kx. => mg - mx" - kx = (M/2)x". => -k(x - mg/k) = [m + M/2](x - mg/k)
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內容預覽:
m1 m2. │﹌﹌█﹌﹌█﹌﹌│. x1→ x2→. (a). m1*d^2x1/dt^2 +kx1+k(x1-x2)=0...(1). m2*d^2x2/dt^2 +kx2+k(x2-x1)=0...(2). where k=3.. (b). Substituting x1=A1cosωt,x2
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