Re: [問題]再一題問題
好像是91政大企研....??
每天發生地震的頻率為 2次/day = λ
令 X 表示 n 天內發生地震的次數, 則: X ~ Poi(nλ) = Poi(2n), 其中 n>0
又令 r.v. Y 表示兩次地震發生, 所間隔的時間, 則:
-2n 0
e (2n) -2n
P(Y>n) = P(X=0) = ────── = e
0!
-2n
F(n) = P(Y≦n) = 1 - P(Y>n) = 1-e
-2n
f(n) = dF(n)/dn = (-2)e , n>0
※ 引述《iverson313 (小艾)》之銘言：
: Suppose that the earthequakes occur in Taiwan follows Poission Distribution
: at a rate of 2 per day.
: Q:Find the probablity distribution of the time,starting from now until the
: next earthquake.
: 拜託高手幫忙囉
: 給個提示也行
: 3Q^^
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06/07 20:07, , 1F
06/07 20:07, 1F
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