[問題] 化學反應速率
這是講義上題目~
感覺好像是很老梗的考題~
但我完全看不懂詳解
題目是
反應方程式
2A+B=3C
t(s) 0 10 20
A(M) 2.0 1.6 1.344
B(M) 1.0 0.8 0.672
其反應速率定律式可能是?
我的想法:
1/2 =0.5
1/1.6 =0.625
1/1.344=0.744
等差~固為2級反應
但我看不懂講義的奇怪解法:
1.6/2.0=0.8/1.0=0.8
(1.6-1.344)/(2.0-1.6)=0.64
0.64=(0.8)^n*(0.8)^m,m+n=2
問題:為什麼算出0.8跟0.64這兩個數據可以當同一時間點?
看似算出的0.8應該是接近5秒時的狀況~
0.64應該是接近10秒時的狀況~
既然時間點不同~為什麼可以直接算呢???(應該是我這裡問題出很大= =)
該不會是把0~10秒跟10~20秒當等速率吧??
希望有好心版有能幫忙解釋一下這到底是在幹什麼@@
※ 發信站: 批踢踢實業坊(ptt.cc)
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