[問題] Google Code Jam 2008, Round 1A - C

看板Prob_Solve作者 (Now of all times)時間12年前 (2012/03/08 00:27), 編輯推噓0(000)
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題目敘述網址: http://code.google.com/codejam/contest/32016/dashboard#s=p2 原本小弟的 algorithm 只能在限定時間內跑完 small dataset, 將 1 <= N <= 1000 印出來觀查後, 發現似乎有以下規律: (1) 個位數 3 -> 1 -> 5 -> 7 四個一組循環 (2) 末兩位 二十個一組循環 (N = 3 開始) (3) 末三位 百個一組循環 (N = 3 開始) 於是加了下面一行後, 用 large dataset 驗證, 結果看來似乎是正確的: if (N > 102) {N %= 100; if (N < 3) {N += 100;}} 但小弟目前還想不懂為何有這樣的規律, 有高手可以解釋一下這個背後是不是有我所不懂的數學原理呢? [小弟的解答 in Java] import java.io.*; import java.util.*; import java.math.*; class C { private static final boolean ECHO_ON = true; private static BufferedReader input; private static BufferedWriter output; private static final BigInteger BIG0 = BigInteger.valueOf(0); private static final BigInteger BIG1 = BigInteger.valueOf(1); private static final BigInteger BIG2 = BigInteger.valueOf(2); private static final BigInteger BIG3 = BigInteger.valueOf(3); private static final BigInteger BIG5 = BigInteger.valueOf(5); private static final BigInteger BIG10 = BigInteger.valueOf(10); private static final BigInteger BIG1000 = BigInteger.valueOf(1000); public static BigInteger sqrt(BigInteger X) { BigInteger answer = BIG1; BigInteger interval = BIG1; for (int i = X.toString().length() / 2; i > 0; i--) interval = interval.multiply(BIG10); while (interval.compareTo(BIG1) >= 0) { while (answer.multiply(answer).compareTo(X) < 0) answer = answer.add(interval); answer = answer.subtract(interval); interval = interval.divide(BIG10); } return answer; } public static void main(String[] args) { try { input = new BufferedReader(new FileReader(args[0] + ".in")); output = new BufferedWriter(new FileWriter(args[0] + ".out")); String line = input.readLine(); int T = getInt(line, 0); for (int i = 1; i <= T; i++) { line = input.readLine(); int N = getInt(line, 0); if (N > 102) {N %= 100; if (N < 3) {N += 100;}} BigInteger X0 = BIG3; BigInteger X1 = BIG1; BigInteger Y0 = BIG1; BigInteger Y1 = BIG0; for (int j = N; j > 0; j /= 2) { if (1 == j % 2) { BigInteger newY0 = X0.multiply(Y0).add(X1.multiply(Y1).multiply(BIG5)); BigInteger newY1 = X0.multiply(Y1).add(X1.multiply(Y0)); Y0 = newY0; Y1 = newY1; } BigInteger newX0 = X0.multiply(X0).add(X1.multiply(X1).multiply(BIG5)); BigInteger newX1 = X0.multiply(X1).multiply(BIG2); X0 = newX0; X1 = newX1; } BigInteger answer = Y1.multiply(Y1).multiply(BIG5); answer = sqrt(answer); answer = answer.add(Y0).mod(BIG1000); String result = "Case #" + i + ": "; String s = answer.toString(); result += (s.length() > 2) ? s.charAt(s.length() - 3) : "0"; result += (s.length() > 1) ? s.charAt(s.length() - 2) : "0"; result += (s.length() > 0) ? s.charAt(s.length() - 1) : "0"; output(result); } input.close(); output.close(); } catch (Exception e) { e.printStackTrace(); } } public static int getInt(String line, int index) { return Integer.parseInt(getString(line, index)); } public static String getString(String line, int index) { int count = 0; line = line.trim(); while (count < index) { line = line.substring(line.indexOf(' ') + 1); count++; } if ((-1) == line.indexOf(' ')) { return line; } else { return line.substring(0, line.indexOf(' ')); } } public static void output(String s) throws Exception { if (ECHO_ON) {System.out.println(s);} output.write(s); output.newLine(); } } -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 59.126.30.95
文章代碼(AID): #1FLunXPN (Prob_Solve)
文章代碼(AID): #1FLunXPN (Prob_Solve)