Re: [問題] 請問如何從incompressible導出另一定義

看板Physics作者 (光太狼)時間2年前 (2021/12/23 00:02), 編輯推噓1(101)
留言2則, 1人參與, 2年前最新討論串2/2 (看更多)
※ 引述《Lanjaja ()》之銘言: : 【出處】(習題或問題的出處) : 看書和上網查有的問題。 : 【題目】(題目的文字敘述,如有圖片亦可提供圖片) : 一般認知的incompressible定義是div(V) = 0 : 可是我在書上和wiki都有提到一種定義是(1/ρ)@ρ/@P ~ 0, : 只是提及,未有證明兩種定義是否有何關係,如何互推。 : 【瓶頸】(解題瓶頸或思考脈絡,請盡量詳述以利回答者知道要從何處講解指導) : 由連續方程式 : @ρ/@t + div(ρV) = 0 : 得到Dρ/Dt + ρdiv(V) = 0 : D是物質微分 : 因為incompressible的條件 : 推到Dρ/Dt = 0 : 再得出@ρ/@t + (@ρ/@P)(DP/Dt) = 0 : 接下來就做不出來了... : 可以請強者幫忙救援一下嗎? : 感謝回答 First of all, we need to know in general, the compressibility itself is a quan tity that depends on the process. So basically, they are different concepts, d iv(v)=0 tells you the fluid is incompressible dynamically, (∂ρ/∂P)_T=0 tell s you the fluid is incomprehensible under isothermic process. If the fluid is flowing isothermically, then they are equivalent in this case, otherwise they may be different. From mass conservation, we know dρ/dt=0 is equivalent to div(v)=0. so the que stion is how to relate dρ/dt to (∂ρ/∂P). As ρ is a thermodynamic intensive quantity, for ordinary fluid, it only has 2 degrees of freedom to control, so if the fluid flows without changes of tempe rature, dρ/dt= (∂ρ/∂P)_T dP/dt, as we know the pressure of a volume elemen t will change as the fluid flows, dρ/dt=0 is equivalent to (∂ρ/∂P)_T=0. -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 47.20.59.170 (美國) ※ 文章網址: https://www.ptt.cc/bbs/Physics/M.1640188940.A.E26.html

12/23 01:23, 2年前 , 1F
謝謝您,但是想確認一下,有沒有argument或證明DP/Dt隨著
12/23 01:23, 1F

12/23 01:24, 2年前 , 2F
流動一定會改變,不等於0,謝謝
12/23 01:24, 2F
文章代碼(AID): #1XmqmCuc (Physics)
文章代碼(AID): #1XmqmCuc (Physics)