Re: [請益] 查詢的語法(php)

看板PHP作者 (花枝)時間17年前 (2007/06/23 22:02), 編輯推噓0(000)
留言0則, 0人參與, 最新討論串1/3 (看更多)
<?php $from=$_POST["textfield4"]; $to=$_POST["textfield5"]; $a=$_POST["radiobutton"]; mysql_select_db($database_aaa, $aaa); $query_Recordset1 = "SELECT * FROM list Where `no` between $from and $to Order by `no`"; $Recordset1 = mysql_query($query_Recordset1, $aaa) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); ?> -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.225.225.96
文章代碼(AID): #16VIWFmi (PHP)
文章代碼(AID): #16VIWFmi (PHP)