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[ Math ]
討論串[中學] 對數問題
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內容預覽:
1.. x = a*10^(-3),1 ≦ a < 10. => log = -3 + log(a). log333 = log(3.33*10^2) = 2 + log3.33. 尾數相同 => a = 3.33. 所以 x = 3.33*10^(-3). 2.. log4.37 = log437
(還有457個字)
內容預覽:
b^2 = ac. => 2 = log a + log c. b b. d = log c - (1/log a) = log c -[1/(2-log c)] ..(1). b b b b. => 2log b = log a + 1. c c. d = log a - (1/log b) =
(還有200個字)